September 20, 2009

PHP MySQL Insert Into

Insert Data Into a Database Table


The INSERT INTO statement is used to add new records to a database table.

Syntax


It is possible to write the INSERT INTO statement in two forms.

The first form doesn't specify the column names where the data will be inserted, only their values:
INSERT INTO table_name
VALUES (value1, value2, value3,...)



second form specifies both the column names and the values to be inserted:

INSERT INTO table_name (column1, column2, column3,...)


Example


we created a table named "Persons", with three columns; "Firstname", "Lastname" and "Age".

We will use the same table in this example. The following example adds two new records to the "Persons" table:


<?php
$con = mysql_connect("localhost","peter","abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("my_db", $con);

mysql_query("INSERT INTO Persons (FirstName, LastName, Age)
VALUES ('Peter', 'Griffin', '35')");

mysql_query("INSERT INTO Persons (FirstName, LastName, Age)
VALUES ('Glenn', 'Quagmire', '33')");

mysql_close($con);
?>


Insert Data From a Form Into a Database.


Here is the HTML form:


<html>
<body>

<form action="insert.php" method="post">
Firstname: <input type="text" name="firstname" />
Lastname: <input type="text" name="lastname" />
Age: <input type="text" name="age" />
<input type="submit" />
</form>

</body>

</html>

When a user clicks the submit button in the HTML form in the example above,

the form data is sent to "insert.php".

The "insert.php" file connects to a database, and retrieves the values from

the form with the PHP $_POST variables.

Then, the mysql_query() function executes the INSERT INTO statement,

and a new record will be added to the "Persons" table.

Here is the "insert.php" page:
<?php
$con = mysql_connect("localhost","peter","abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("my_db", $con);

$sql="INSERT INTO Persons (FirstName, LastName, Age)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";

if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";

mysql_close($con)
?>




Disqus Comments